How many bytes would s9 9 v99 occupy

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WebJan 17, 2013 · If this "number" is always guaranteed to have the same format: 7 digits, a decimal point and 2 more digits after the decimal, the classic way of doing this in COBOL is: 01. 02 NUM-AS-PIC PIC X (10). 03 NUM-EDITED REDEFINES NUM-AS-PIC PIC 9 (7).99. 01 NUM-DEEDITED PIC 9 (7)V99. MOVE '1234567.89' TO NUM-AS-PIC <- alpha-numeric move … WebOct 3, 2016 · S9 (9)V99 is X'99999999999S' or six bytes. S9 (8)V99 is X'09999999999S' or six bytes. S9 (7)V99 is X'999999999S' or five bytes. For COMP, I suggest that you look it …

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WebAnswer / naveen87ginjupalli S9 (5)V9 (2) occupies 7 bytes of memory. Here V doesn't occupies any space it assumes internally.V is the assumed Decimal point, it is used to … Webhow many bytes does s9 (15) occupy in comp1 comp2 and comp3 ?.. Answer / rana. COMP1 and COMP2 are the Single precision (Full word - 4. bytes) and Double precision (Double word - 8 bytes) respectively. They don't contain the Picture Clause. COMP-3 will contain 8 Bytes. bju theatre department

How many bytes will a S9(8) COMP field occupy ? Dell India …

WebApr 14, 2024 · 9 (5)-9 (9) = 4 bytes 9 (10)-9 (18) = 8 bytes.. 9 (3)v9 (7) occupies 8 bytes but the question itself wrong COMP variable doesnt have a PIC clause bcz it already contains … WebSep 25, 2007 · The intent of this data type is to make it the most efficient format on any given machine, which is usually some binary format. Because of this, comp varies greatly … WebHow many bytes would S9 (9)V99 occupy? A) 11 B) 12 C) 6 D) 13 Can index be manipulated using ADD & SET verbs A) Yes B) No (Only Set) Identify the correct statement. A) … datrex emergency water pouch

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WebPIC S9(_) USAGE COMP-5. PIC 9(_) USAGE COMP-5. Length 1 to 4 SQL_Smallint. Length 5 to 9 SQL_Integer. Length 10 to 18 SQL_Binary ... Storage representation Numeric values; S9(1) through S9(4) S9(5) through S9(9) S9(10) through S9(18) Binary half-word (2 bytes) Binary full-word (4 bytes) Binary double-word (8 bytes)-32768 to +32767-2,147,483,648 ... WebDec 9, 2024 · 01 WS-NUM PIC S9(5)V9(3) USAGE IS DISPLAY. It requires 8 bytes as sign and decimal doesn't require any byte. 01 WS-NUM PIC 9(5) USAGE IS DISPLAY. It requires 5 bytes as sign. COMPUTATIONAL / COMP Data item is stored in binary format. Here, data items must be integer. bju the utWebJan 2, 2024 · 03 num-2 pic s9(5)v99 comp. 03 num-3 pic s9(5)v99 comp-3. Share. Improve this answer. Follow answered Jan 3, 2024 at 0:57. Bruce Martin Bruce Martin. 10.3k 1 1 gold badge 26 26 silver badges 37 37 bronze badges. Add a comment Your Answer Thanks for contributing an answer to Stack Overflow! ... datrek golf bags university of connecticut

"Web13 rows · Dec 14, 2012 · Storage Length (bytes) BYTEINT: 1: PIC S9(3) COMP: Integer: 3: n/a: 2: CHAR: n: PIC X(n) Char: ... " - How many bytes would s9 9 v99 occupy

How many bytes would s9 9 v99 occupy

What is the maximum value that can be stored in pic s9(9) v9(2

WebByte size = (7 + 1) / 2 = 4 PIC S9 (5)V99 COMP-3. Byte size = (5 + 2 + 1) / 2 = 4 PIC S9 (6) COMP-3. Byte size = (6 + 1) / 2 = 3.5, rounded to 4 Comp-3 fields reserve a nybble for the sign, even for "unsigned" values, so the following fields are still 4 bytes: PIC 9 (7) COMP-3. Byte size = (7 + 1) / 2 = 4 PIC 9 (6) COMP-3. WebApr 22, 2006 · The COMP occupies Int (n/2) 4 bytes and COMP-3 occupies Int ( (n/2)+1) bytes. So using this we get the results as : S9 (4) COMP - Int (4/2) = 2 bytes S9 (5) COMP - …

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WebApr 9, 2010 · Unless you need a sign-nibble for the last-byte, move the S9 (11)V99 field to a 9 (11)V99 work-field and the sign-nibble will be dropped. When signed (and I'm assuming positive), the last byte will be in the range of X'C0' through X'C9'. WebData name length Length in COBOL 9(01) to 9(04) 2 bytes 9(05) to 9(09) 4 bytes S9(10) to S9(18) 8 bytes COMP-1:In this case the data item will be represented in one word in the floating point form the number is actually represented in hexadecimal format and is suitable for arithmetic operations. The PICTURE Clause cannot be specified for COMP-1 ...

Webs9 (9)v9 (9) Here v stands for assumed decimal point so it will occupy. only 18 bytes (9+9)...if instead of s9 (9)v9 (9) it is coded as. s9 (9).9 (9) then it is going to occupy 19 … WebOn the other hand, a COBOL S9(9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits followed by a C or D as the last HEX digit for the sign. In this case, S9 means it is a signed numeric field. The (9)V99 means that this number is composed of 1 integral position

WebPIC S9(5)V99 ZD7.2 Field is 7 bytes long, PIC S9(5)V999 ZD8.3 Field is now 8 bytes, and last 3 digits are decimals PIC S9(5)V99 COMP-3 PD4.2 4 bytes long, of which last 2 digits are …

WebJun 24, 2004 · 05 OUT-AMT PIC S9(15)V99. or if you want numeric edited: 05 OUT-AMT PIC -(15)9.99 BLANK WHEN ZERO. Hope This Helps, PH. ... occupy 9 bytes. I would have …

WebAug 26, 2024 · For WS-VALC PIC S9 (3) USAGE IS COMP-3, so here we can take it as (3+1)/2 which is equal to 2bytes size. Similarly, in the 3byte variable which is WS-VALD PIC S9 (4) USAGE IS COMP-3, so here we can take it as (4+1)/2 which is equal to 2.5 (rounded off) so it will take 3bytes. 10. How to Install COBOL on MacOS? Previous Program Structure of … bju twitterWebJan 8, 2003 · On the other hand, a COBOL S9 (9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits … dat right choiceWebAn integer (INT) is a 4-byte integer SQL data type that can be declared in COBOL with usage BINARY, COMP, COMP-X, COMP-5 or COMP-4. All of the following definitions are valid for host variables to map directly onto the INT data type. 03 longint1 PIC S9(9) COMP. 03 longint2 PIC S9(9) COMP-5. 03 longint3 PIC X(4) COMP-5. bju theatreWebJun 24, 2004 · If OUT-AMT is not used in this program (and it's unlikely that it is), it is not necessarily an error as the cited comp-3 field does, in fact, occupy 9 bytes. I would have either defined it as filler, or, more accurately, defined it to match AMOUNT of IN-REC (including the COMP-3). bjut wifiWebPIC S9(5) ZD5. ZD for zoned-decimal PIC S9(5)V99 ZD7.2 Field is 7 bytes long, PIC S9(5)V999 ZD8.3 Field is now 8 bytes, and last 3 digits are decimals PIC S9(5)V99 COMP-3 PD4.2 4 bytes long, of which last 2 digits are decimals PIC 9(5)V99 COMP-3 PK4.2 Same as above but unsigned (this is rare) PIC 9(8) COMP IB4. Integer binary (signed) YYMMDD8. datrek golf case repair partsWebSep 14, 2007 · Mainframe Interview Questions: How many bytes will S9(12)V99 COMP-3 occupy? Answer: 1) 7 2) 9 3) 8 4) 6 5) 10 : How many bytes will S9(12)V99 COMP-3 occupy: IBM Mainframe Forums-> Mainframe Interview Questions : Quick References View previous topic:: View next topic : Author Message; Lavanya_Dhushetty Warnings : 2 bjut universityWebJan 8, 2003 · (9)V99 means that this number is composed of 1 integral position followed by 2 decimal places. The V in the V99 is implies that there are decimal places to follow. For example: If the number... datrin industry co. ltd